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y(1) and y(2) and y(3) are the ordinates...

`y_(1) and y_(2) and y_(3)` are the ordinates of three points on the parabola `y ^(2) = 4ax,` then the area of the triangle formed by the points is-

A

`|(1)/(4a) (y_(1)-y_(2)) (y_(2)-y_(3)) (y_(3) -y_(1))|`

B

`|(1)/(16a) (y_(1)-y_(2)) (y_(2)-y_(3)) (y_(3) -y_(1))|`

C

`|(1)/(2a) (y_(1)-y_(2)) (y_(2)-y_(3)) (y_(3) -y_(1))|`

D

`|(1)/(8a) (y_(1)-y_(2)) (y_(2)-y_(3)) (y_(3) -y_(1))|`

Text Solution

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The correct Answer is:
D
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