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Prove that, sec^2theta+cosec^2theta=sec^...

Prove that, `sec^2theta+cosec^2theta=sec^2theta*"cosec"^2theta.`

Text Solution

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The correct Answer is:
`=1/(cos^2theta)*1/(sin^2theta)=sec^2theta*"cosec"^2theta=R.H.S`
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