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(cotalpha+"cosec"alpha-1)/(cotalpha-"cos...

`(cotalpha+"cosec"alpha-1)/(cotalpha-"cosec"alpha+1)=(1+cosalpha)/(sinalpha)`

Text Solution

Verified by Experts

The correct Answer is:
`(cosalpha)/(sinalpha)+1/(sinalpha)=(1+cos alpha)/(sinalpha)=R.H.S`
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