Home
Class 12
MATHS
If sin^4x+sin^2x=1 show that, cot^4x+co...

If `sin^4x+sin^2x=1` show that, `cot^4x+cot^2x=1`

Text Solution

Verified by Experts

The correct Answer is:
`therefore cot^4x+cot^2x=cos^2x+sin^2x=1`
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC RATIOS [OR FUNCTIONS] OF POSITIVE ACUTE ANGLES

    CHHAYA PUBLICATION|Exercise EXERCISE 2|94 Videos
  • TRIGONOMETRIC RATIOS [OR FUNCTIONS] OF POSITIVE ACUTE ANGLES

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams|1 Videos
  • TRIGONOMETRIC RATIOS OF MULTIPLE ANGLES

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos
  • VECTOR

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITIVE EXAMINATION|18 Videos

Similar Questions

Explore conceptually related problems

if sin^4x+sin^2x=1 ,then prove that cot^4x+cot^2x =1.

If cos^4x/cos^2y+sin^4x/sin^2y=1 ,show that cos^4y/cos^2x+sin^4y/sin^2x=1

If (cos^4x)/(cos^2y)+(sin^4x)/(sin^2y)=1,"show taht", (cos^4y)/(cos^2x)+(sin^4y)/(sin^2x)=1

Fill in the blanks : If sin^(4)A+sin^(2)A=1 , then cot^(4)A+cot^(2)A= __________ .

If x-1/x = 2i sin theta, "show that", x^(4)-1/x^(4)=2i sin 4 theta.

Show that, cot2xcotx-cot3xcot2x-cot3xcotx=1

If 0 lt x lt pi and sin x+ sin^(2) x+ sin^(3)x=1 , find the minimu value of cot^(2)x.

lim_(x->oo)(sin^4x-sin^2x+1)/(cos^4x-cos^2x+1) is equal to (a) 0 (b) 1 (c) 1/3 (d) 1/2

"if " sin^(-1) x +sin ^(-1) y+sin ^(-1) z=pi show that , x^(4)+y^(4)+z^(4)+4x^(2)y^(2)z^(2)=2(x^(2)y^(2)+y^(2)z^(2)+z^(2)x^(2))

If y=(sin^4x-cos^4x+sin^2xcos^2x)/(sin^4x+cos^4x+sin^2xcos^2x),x in (0,pi/2) , then (a) -3/2lt=ylt=1/2 (b) 1lt=ylt=1/2 (c) -5/3lt=ylt=1 (d) none of these

CHHAYA PUBLICATION-TRIGONOMETRIC RATIOS [OR FUNCTIONS] OF POSITIVE ACUTE ANGLES-Sample Questions for Competitive Exams (Assertion -Reason Type )
  1. If sin^4x+sin^2x=1 show that, cot^4x+cot^2x=1

    Text Solution

    |

  2. Statement -I : cos 1 lt cos 7 Statement -II: In 1st quadrant the val...

    Text Solution

    |

  3. Find the principal value of sin^-1(-1)

    Text Solution

    |