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If sec theta=(2xy)/(x+y)^2 show that, x^...

If `sec theta=(2xy)/(x+y)^2` show that, `x^2+y^2=1 `
`(sinalpha cos alpha ne 0)`

Text Solution

Verified by Experts

The correct Answer is:
`therefore x^2+y^2=cos^2alpha +sin^2alpha=1`
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