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ABC is a triangle where a=6, b=3 and cos...

ABC is a triangle where a=6, b=3 and `cos(A-B)=4/5`
(i) Area of the triangle ABC (in sq. units) is-

A

9

B

12

C

11

D

10

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 Value of angle C is-

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    `(3pi)/4`
    B
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    xy
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    `sqrt3xy`
    D
    4xy
  • In a triangle ABC if b=2, B=30^(@), then the area of the circumcircal of triangle ABC in square units is-

    A
    `6pi`
    B
    `4pi`
    C
    `2pi`
    D
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