Home
Class 12
MATHS
From the sequence [5, 7, 9, 11, ….], pre...

From the sequence [5, 7, 9, 11, ….], prepare the series of first n terms.

Text Solution

Verified by Experts

The correct Answer is:
`5+7+9+11+…+ (2n+3)`
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE AND SERIES

    CHHAYA PUBLICATION|Exercise Example|7 Videos
  • SEQUENCE AND SERIES

    CHHAYA PUBLICATION|Exercise Exercise 9 A (Multiple Choice Questions)|4 Videos
  • SECOND ORDER DERIVATIVE

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination (Assertion-Reason type)|2 Videos
  • SET THEORY

    CHHAYA PUBLICATION|Exercise Assertion-Reason Type|2 Videos

Similar Questions

Explore conceptually related problems

If first three terms of the sequence 1/16 ,a , b , 1/6 are in geometric series and last three terms are in harmonic series, then find the values of a , bdot

If A.M., G.M., and H.M. of the first and last terms of the series of 100 , 101 , 102 ,...(n-1),n are the terms of the series itself, then the value of n is (100ltnlt500)

The rth term of a series is (2r + 1)2^(r ) , find the sum of first n terms of the series.

There is a certain sequence of positive real numbers. Beginning from the third term, each term of the sequence is the sum of all the previous terms. The seventh term is equal to 1000 and the first term is equal to 1 . The second term of this sequence is equal to

If the sum of the first n terms of a G.P. = p and the sum of the first 2n terms = 3p, show that the sum of first 3n terms = 7p.

If the sum of first n terms of a G.P is p and the sum of the first 2n terms is 3p,show that the sum of first 3n terms is7p.

Determine the first five terms of the sequence defined by, u_(1) = 4 and u_(n) = 3u_(n-1) + 2 for n ge 2 . Also find the series of first five terms of the sequence.

The nth term of a series is 3^(n) + 2n , find the sum of first n terms of the series.

If the nth term of a series be (2.3^(n-1) + 1) , find the sum of first r terms of the series.

Find the sum of the sequence 7, 77, 777, 7777, ... to n terms.