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If S(r ) be the sum of the cubes of firs...

If `S_(r )` be the sum of the cubes of first r natural numbers, then show that `Sigma_(r=1)^(n) (2r+1)/(S_(r)) = (4n(n+2))/((n+1)^(2))`, for any natural number n.

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The correct Answer is:
`(4n(n+2))/((n+1)^(2))`
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