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If S(n) = 1^(2) - 2^(2) + 3^(2) - 4^(2) ...

If `S_(n) = 1^(2) - 2^(2) + 3^(2) - 4^(2) + 5^(2) - 6^(2) +…`, then-

A

`((a+c)(3a-c))/(4a^(2)c^(2))`

B

`(2)/(bc) - (1)/(b^(2))`

C

`(2)/(bc) - (1)/(a^(2))`

D

`((a-c)(3a + c))/(4a^(2)c^(2))`

Text Solution

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The correct Answer is:
A,B
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