Home
Class 12
MATHS
Find the centre of the circle whose para...

Find the centre of the circle whose parametric equations are `x = - (1)/(2) (1 + 5 cos theta ) , y = (1)/(2) (-2 + 5 sin theta) ` .

Promotional Banner

Topper's Solved these Questions

  • COORDINATE GEOMETRY

    CHHAYA PUBLICATION|Exercise WBHS Archive (2014)|16 Videos
  • COORDINATE GEOMETRY

    CHHAYA PUBLICATION|Exercise WBHS Archive (2015)|10 Videos
  • COORDINATE GEOMETRY

    CHHAYA PUBLICATION|Exercise JEE Advanced Archive (2016)|3 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (Assertion - Reason Type)|2 Videos
  • DEFINITE INTEGRAL

    CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITIVE EXAMINATION ( ASSERTION-REASON TYPE )|2 Videos

Similar Questions

Explore conceptually related problems

Find the equation to the circle whose parametric equations are, x = (1)/(2)(1+5 cos theta), y = (1)/(2)(-2 + 5sin theta)

Find the centre of the circle whose parametric equation is x= -1+2 cos theta , y= 3+2 sin theta .

Find the equation of the curve whose parametric equations are x=1+4costheta,y=2+3sintheta,theta in R .

The parametric equations of a circle are, x = (1)/(2)(-3+4 cos theta), y = (1)/(2)(1+4 sin theta) . Find the equation of the circle.

If theta be a variable parameter find the curve whose parametric equations are x=1/4(3-cosec^2theta)&y=2+cottheta

sin theta+ 2cos theta =1

The centre of the circel x=2+3 cos theta, y= 3 sin theta -1 is-

Find the parametric equation of the circle x^(2) + y^(2) - 5x + 2y + 5 = 0 .

Eliminate theta : x = a ( cos theta + cos 2 theta), y = b ( sin theta + sin 2 theta).

Find the parametric equation of the circle x^(2) + y^(2) + 4x - 8y - 5 = 0 .