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If the circles x^(2) + y^(2) + 2x + 2ky...

If the circles `x^(2) + y^(2) + 2x + 2ky + 6 = 0 ` and `x^(2) + y^(2) + 2ky + k = 0 ` intersect orthogonally , then k is equal to _

A

`2 or -(3)/(2)`

B

`-2 or -(3)/(2)`

C

`2 or (3)/(2)`

D

`-2 or (3)/(2)`

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The correct Answer is:
A
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CHHAYA PUBLICATION-COORDINATE GEOMETRY-WBJEE Archive (2012)
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