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Let us consider one vertex and one side through the vertex along x -axis of a triangle . Now the coordinates of the vertices B,C and A of any triangle ABC (0,0) ,(a,0) and (h,k) respectively should be taken .
If in triangle ABC , AC =3 ,BC=4 and median AD is perpendicular with median BE , then the area of `DeltaABC` is -

A

`sqrt(7)` sq . Units

B

`sqrt(11)` sq . Units

C

`2sqrt(2)` sq. units

D

none of these

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Let us consider one vertex and one side through the vertex along x -axis of a triangle . Now the coordinates of the vertices B,C and A of any triangle ABC (0,0) ,(a,0) and (h,k) respectively should be taken . If internal bisector of angle angleA of the triangle ABC intersects BC at D such that BD =4 and DC =2 then -

    A
    `ACgt6andABgt4`
    B
    `2ltAClt6andABlt1`
    C
    `2ltAClt6and4ltABltK`
    D
    none of these

  • Let us consider one vertex and one side through the vertex along x -axis of a triangle . Now the coordinates of the vertices B,C and A of any triangle ABC (0,0) ,(a,0) and (h,k) respectively should be taken . If the altitude (AE) of the triangle in question (ii) greater than sqrt(10) and the lenght of AB and AC are of integral value , then the lenght of AC is -

    A
    3
    B
    6
    C
    4 or 5
    D
    none of these

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