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Center of the circle x^(2) + y^(2) - 4x ...

Center of the circle `x^(2) + y^(2) - 4x + 6y - 12 = 0` is -

A

(2, 3)

B

(2, -3)

C

(-2, 3)

D

(-2, -3)

Text Solution

Verified by Experts

The correct Answer is:
B
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Determine the positions of the points (-1, 2) with respect to the circle x^(2) + y^(2) - 4x + 6y + 4 = 0 .

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