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Points (2k, 3k), (1, 0), (0, 1) and (0, ...

Points (2k, 3k), (1, 0), (0, 1) and (0, 0) will be concyclic if the value of k is equal to-

A

k=0

B

k=1

C

`k = (5)/(13)`

D

k=5

Text Solution

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The correct Answer is:
A, C
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