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If f (a) = 2 , f'(a) = 1, g (a) = -1 an...

If `f (a) = 2 , f'(a) = 1, g (a) = -1` and `g'(a) = 2 , ` show
that `lim_(x to a)(g(x)f(a)-f(x)g(a))/(x-a) = 5`

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The correct Answer is:
`= * 2 = (-1)* 1 = 5 `
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