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If f(x) = |x-3| + 2 , evalute lim(x ...

If `f(x) = |x-3| + 2 ` , evalute ` lim_(x to 3 + ) (f(x)-f(3))/(x-3)` and ` lim_(x to 3 - ) (f(x)-f(3))/(x-3)`
Hence examine the differentiability of `f(x)` at x = 3 .

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The correct Answer is:
1 and `-1` , not differentiable
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