Find the probability that a leap year, selected at random will contain 53 Sundays.

Find the probability that a leap year selected at random will contain 53 Mondays.

What is the probability that a non leap year selected at random will contain 53 sundays?

The probability that a leap year selected at random will contain 53 Sundays is (K)/(7) , then find the value of K.

The probability that a non-leap year selected at random will have 53 Sundays is

What is the chance that a leap year selected at random will contain 53 Sundays ?

What is the chance that a leap year selected at random will contain 53 sundays?

What is the chance that a leap year selected at random will contain 53 Mondays? Find also the probability of having 53 Mondays in a year, which is not a leap year.

In a group consisting of 80 men and 30 women, 15 per cent men and 40 per cent women are unemployed . Find the probability that a person selected at random is employed.

What is the probability that a year, selected at random, in between 2001 and 2010 (both inclusive) will contain 53 Mondays ?

A box contains 15 balls numbered 1 to 15. Find the probability that a ball selected at random would bear a number that is a multiple of 3 or 5.