Show that the non-mutually exclusive eve...

Show that the non-mutually exclusive events A and B,
`P(A cup B) = P(A) + P(B) - P(AcapB)`.

PROBABILITY
CHHAYA PUBLICATION|Exercise SAMPLE QUESTIONS FOR COMPETITIVE EXAMS|18 Videos
PROBABILITY
CHHAYA PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS|46 Videos
PLANE
CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination( E Assertion - Reason Type )|2 Videos
PRODUCTS OF TWO VECTORS
CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (Assertion - Reason Type )|2 Videos

Similar Questions

Explore conceptually related problems

Show that for two non-mutually exclusive events A and B, P(A cup B)=P(A) +P(B)-P(A cap B)

For any two events A and B, show that, P(A uu B) = P(A) + P(B) - P(A nn B) .

For any two events A and B prove that, P(A cup B) le P(A) + P(B)

If the events A and B are not mutually exclusive then P(A cup B) =

If A and B are two mutually exclusive event then P(A-B) =

If A and B are two mutually exclusive events and P(A cup B) ne 0 , then show that, P[A//(A cup B)] =(P(A))/(P(A)+P(B)) .

If A and B are mutually exclusive events, then (a) P(A) le P(barB) (b) P(A) gt P(B) (c) P(B) le P(barA) (d) P(A) gt P(B)

For any two events A and B prove that P(A cup B) le P{A) + P (B) .

Show that the probability that exaclty one of the events A and B occurs is P(A) + P(B) - 2P(AB).

Show that the probability that exactly one of the events A and B occurs is P(A) + P(B) - 2P(AB).