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From 100 tickets numbered 1, 2, 3, ........

From 100 tickets numbered `1, 2, 3, ...... , 100`, four are drawn at random. What is the probability that 2 of them will bear numbers from 1 to 40 and the other 2 will bear any number from 41 to 100?

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The correct Answer is:
`(""^(40)C_(2)xx^(60)C_(2))/(100_(C_(4)))`
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