lim(x rarr 0) (log(e)(1+x))/(3^(x) - 1)=...

`lim_(x rarr 0) (log_(e)(1+x))/(3^(x) - 1)=`

`log_(e)3`

`log_(3) e`

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The correct Answer is:

lim(x rarr 3) (x^(2) - 9)/(x-3)=
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lim(x rarr 1) (1-x) tan ((pix)/(2))=
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lim(x rarr 0) (log(e)(1+x))/(3^(x) - 1)=
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lim(x to 7)(2-sqrt(x-3))/(x^(2) - 49)=
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lim(x rarr 0) (2^(x) - 1)/(sqrt(1+x)-1)=
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lim(x rarr 0) (sin x)/(x) =
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यदि lim(x rarr 0)(log(3+x)-log(3-x))/(x)=k हो, तो k का मान है -
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lim(a rarr beta) (sin^(2)alpha - sin^(2)beta)/(alpha^(2) - beta^(2))=
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lim(x rarr oo) ((x+2)/(x+1))^(x+3)=
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lim(x rarr 0) (tan x - sin x)/(x^(3))=
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lim(x to 0)((1+x)^8-1)/((1+x)^2-1) का मान है :
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lim(x rarr 0) (sin x - tan x)/(cos x - sec x)=
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lim(x rarr 0) (x cos x - log(e)(1+x))/(x^(2))=
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lim(x rarr 0) (sqrt(x^(2)+1)-1)/(sqrt(x^(2) + 9)-3)=
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lim(x rarr 0) ((1+tan x)/(1+sin x))^("cosec x")=
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lim(x rarr oo) ((x-3)/(x+2))^(x)=
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यदि lim(x rarr a) (logx-log a)/(x-a) + k lim(x rarr e) (log x - 1)/(...
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lim(x rarr 1) (log x)/(x-1)=
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lim(x to 0)(sqrt((1-cos 2x)/(2)))/(x)=
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यदि lim(x rarr 1) (x^(4) - 1)/(x-1)=lim(x rarr k) (x^(3) - k^(3))/(x^(...
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