An `L.P.G` cylinder contains `15kg` of butane gas at `27^(@)C` and 10 atm pressure It was leaking and its pressure fell down to 8 atm pressure after one day Calculate the amount of leaked gas .

Options

A. 1 kg
B. 2 kg
C. 3 kg
D. 4 kg

Answer

C

Explanation

For cylinder V =constant
`P_(1)/P_(2)=n_(1)/n_(2)" "P_(1)/P_(2)=W_(1)/W_(2)`
`(10)/(8)=(15)/(x) :.`x=12 Kg
Hence gas leaked =15-12=3 Kg