The integrated form of Clausius-Clapeyron equation is

Options

A. `(dlnK)/(dT)=(DeltaH)/(RT^(2))`
B. `"log"_(10)"K_(2)/(K_(1))=(DeltaH)/(2.303R)((1)/T_(1)-(1)/(T_(2)))`
C. `"log"_(10)"P_(2)/(P_(1))=(Hvap)/(2.303R)((1)/T_(1)-(1)/(T_(2)))`
D. None of these

Answer

C

Explanation

Clausius-Clapeyron equation is `(dInP)/(dT)=(L_(v))/(RT^(2))`
It gives variation of V.P.(P) with temperature T or effect of pressure on the boiling point. The integrated form is
log `P_(2)/P_(1)=L_(v)/(2.303R)((1)/(T_(1))-(1)/T_(2))`