The density of a gas at `27^(@)C` and `1 atm` is `d`. Pressure remaining constant, at which of the following temperture will its density become `0.75 d`?

Options

A. `20^(@)` C
B. `30^(@)` C
C. 400 K
D. 300 K

Answer

C

Explanation

`d=(PM)/(RT)=,d_(1)/(d_(2))=P_(1)/T_(1).T_(2)/P_(2)=T_(2)/T_(1)( "as"P_(1)=P_(2))`
`(d)/(0.75)=T_(2)/(300),T_(2)`=400K