In case of Boyle's law, if the pressure is increased by 1% the percentage decrease in volume is

Options

A. 0.01
B. `(100)/(101)`%
C. `(1)/(100)`%
D. `(1)/(100)`%

Answer

B

Explanation

`P_(1)V_(1)=P_(2)V_(2)`
If `P_(1)`=100 mm, `P_(2)` will be 101 mm.
Hence `100xxV =101 xxV_(2),V_(2)=(100)/(101)xxV`
Decreases om volume =` V-(100V)/(101)=(1)/(101) `of V,
i.e, `(100)/(101) %`