The temperature of the gas is raised from `27^(@)C` to `927^(@)C`, the root mean square velocity is

Options

A. `sqrt(927//27)` times the earlier value
B. same as before
C. halved
D. doubled

Answer

D

Explanation

`u=sqrt((3RT)/(M))" " "or" " " (u_(1))/(u_(2))=sqrt((T_(1))/T_(2))`
`=sqrt((27+273)/(927+273))=sqrt((300)/(1200))=(1)/(2)`
`u_(2)=2u_(1)`