The work done in ergs for the reversible expansion of one mole of an ideal gas from a volume of `10` litres to `20` litres at `25^(@)C` is

Options

A. `-2.303xx298xx0.082xx log_(10^(2))`
B. `-2.303xx298xx0.082xxlog_(10^(0.5))`
C. `-2.303xx298xx8.2xx10^(7) xx log_(10^(2))`
D. `-2.303xx298xx2xx log_(10^(2))`

Answer

C

Explanation

`W_("max")=-2.303" nRT "log_(10)(V_(1))/(V_(2))`
`R=8.2 J=8.2 xx 10^(7)` ergs
`therefore W_("max")=-2.303 xx 1xx8.2 xx10^(7) xx298xxlog_(10)(20)/(10)`
`W_("max")=-2.303xx8.2xx10^(7)xx298xxlog_(10)^(2)`