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The external pressure needed to compress...

The external pressure needed to compress an ideal gas from `22 dm^(3)" to "8 dm^(3)` if work done is of 4.545 kJ is

A

`3.03xx10^(5) Nm^(-2)`

B

`2.03xx10^(5) Nm^(-2)`

C

`1xx10^(5) Nm^(-2)`

D

`-3.4xx10^(5) Nm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Work done `W=4.545 kJ =4545 J`
`Delta V=22-8=14 dm^(3)`
`=14xx10^(3)m^(3)`
`W= P Delta V`
`=(W)/(Delta V)=(4545)/(14xx10^(-3))`
`P=3.03xx10^(5)" Nm"^(-2)`
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