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Calculate the work done when 1.0 mol of ...

Calculate the work done when `1.0` mol of water at `373K` vaporises against an atmosheric pressure of `1.0atm`. Assume ideal gas behaviour.

A

- 6200 J

B

-306 J

C

-3100 J

D

-1550 J

Text Solution

Verified by Experts

The correct Answer is:
C
Volume of 1 mole of `H_(2)O" at "373 K` and 1 atm
`(V_(1))=18cm^(3)=0.018 L`
Volume of 1 mole of `H_(2)O` vapour at 373 K and 1 atm (PV=RT)
`V_(2)=(RT)/(P)=(0.0821xx373)/(1)=30.60 L`
`W=-P(V_(2)-V_(1))=-1(30.62-0.018)=-30.6 L" atm "=-30.6xx101.3=-3100 J`
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