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A person requires 2870kcal of energy to ...

A person requires `2870kcal` of energy to lead normal daily life. If heat of combustion of cane sugar is `-1349kcal`, then his daily comsumption of sugar is `:`

A

728

B

728

C

342

D

342

Text Solution

Verified by Experts

The correct Answer is:
B
Molecular weight of cane sugar `(C_(12)H_(22)O_(11))=342`
342 g or 0.342 kg of cane sugar gives 1349 kcal energy. `therefore X kg` of cane sugar gives 2870 kcal energy
`(X)/(0.342)=(2870)/(1349)`
`therefore X=(2870)/(1349)xx0.342`
`=2.12xx0.342 =0.728 kg`
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