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HA+OH^(-) to H(2)O+A^(-)+q(1) kJ H^(+)...

`HA+OH^(-) to H_(2)O+A^(-)+q_(1) kJ`
`H^(+)+OH^(-) to H_(2)O+ q_(2) kJ`
The enthalpy of dissociation of `HA` is

A

`(q_(1)+q_(2))`

B

`(q_(1)-q_(2))`

C

`(q_(2)-q_(1))`

D

`-(q_(1)+q_(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(HA+OH^(-) rarr H_(2)O+A^(-) +q_(1) kJ),(H_(2)O+q_(2)kJ rarr H^(+) +OH^(-)):}/(HA rarr H^(+) +A^(-), Delta H= (q_(2)-q_(1))kJ)`
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