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The enthalpy change for the following re...

The enthalpy change for the following reactions are:
`C_("diamond")+O_(2(g)) rarr CO_(2(g))" "DeltaH=-395.3 KJ "mol"^(-1)`
`C_("graphite")+O_(2(g)) rarr CO_(2(g)) " "DeltaH=-393.4 KJ "mol"^(-1)`
The enthalpy change for the transition
`C_("diamond")rarr C_("graphite")` will be :

A

+ 1.5 KJ

B

- 1.5 KJ

C

`-799.5`

D

`+788.5`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_("graphite") rarr C_("diamond") " "Delta H=?`
`Delta H = Delta H_(c) ("graphite")-H_(c) ("diamond")`
`Delta H=-393.5 - (-395)=-393.5 +395`
`Delta H =+ 1.5` kJ
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