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The enthalpy of vaporization of a substa...

The enthalpy of vaporization of a substance is 840 J per mol and its boiling point is `-173^@C`. Calculate its entropy of vaporization.

A

`8.4 J mol^(-1) K^(-1)`

B

`21 JK^(-1) mol^(-1)`

C

`49 J mol^(-1) K^(-1)`

D

`12 J K^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta S_("vap")=(Delta H_("vap"))/(T_(b))=(840)/(100)=8.4 JK^(-1) mol^(-1)`
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