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For the equilibrium PCl(5)hArr PCl(3)(g)...

For the equilibrium `PCl_(5)hArr PCl_(3)(g)+Cl_(2)(g)` at `298 K, K_(p)=1.8xx10^(-7)`. What is `Delta G^(@)` for the reaction ?

A

`+9197.5 cal`

B

`-9197.5 cal`

C

`+771 cal`

D

`-7716 cal`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta G^(@) =- RT//n k_(p)`
`=-2.303 RT log k_(p)`
`=-2.303 xx1.987 xx298 log 1.8 xx10^(-7)`
`=-2.303 xx 1.987 xx298 (-6.7447) =9197.5 cal`
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