Home
Class 12
CHEMISTRY
1 L atm is equal to ....

1 L atm is equal to ____ .

A

28.2 cal

B

202 cal

C

12.2 cal

D

24.2 cal

Text Solution

Verified by Experts

The correct Answer is:
D
Refer nature of heat and work.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS AND ENERGETICS

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (TEST YOUR GRASP)|50 Videos

  • CHEMICAL THERMODYNAMICS AND ENERGETICS

    MARVEL PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (HIGHER LEVEL)|112 Videos

  • CHEMICAL KINETICS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|50 Videos

  • CHEMISTRIY IN EVERYDAY LIFE

    MARVEL PUBLICATION|Exercise TEST YOUR GRAPS|24 Videos

Similar Questions

Explore conceptually related problems

Calculate pressure (in atm) of a Vander-waal gas taken at temperature of 399K if its density is equal to 12gm//L . Given : a= 6.4 atm-litre^2 mol^(-2) and b=0.01 L mol^(-1) molar mass = 48, R=0.0821 atm-L mol^(-1) K^(-1)

The osmotic pressure M/10 solution of cane sugar (Molar mass 342 g mol-1) at 300 K equal to [R = 0.082 L atm k ^(-1) mol^(-1) ):

Knowledge Check

  • For which of the following equations is the enthapy change at 25^(@)C and 1 atm equal to DeltaH_(f)^(@)(CH_(3)OH,l)

    A
    `CO(g)+2H_(2)(g)rarrCH_(2)OH(l)`
    B
    `CO(g)+4H(g)+O(g)rarrCH_(3)OH(l)`
    C
    `CO(g)+4H(g)+O(g)rarrCH_(3)OH(l)`
    D
    `C` (graphite) `+2H_(2)(g)+(1)/(2)O_(2)(g)rarrCH_(3)OH(l)`

  • 1 L atm=? J Given 1 atm = 101325 Pa

    A
    101.325 J
    B
    10.1325 J
    C
    1013.25 J
    D
    10132.5 J

  • If 1.5 L of an ideal gas at a apressure of 20 atm expands isothermally and reversibly to a final volume of 15 L, the work done by the gas in L atm is:

    A
    69.09
    B
    34.55
    C
    `-34.55`
    D
    `-69.09`

    • Similar Questions

    Explore conceptually related problems

    Calculate the amount of work done when one mole of an ideal gas contained in a bulb of 2 L capacity at 1 atm is allowed to enter in evacuted bulb of 10 L capacity and in another case if is allowed to expand from 1 L to 5 L against a pressure of 1 atm.

    A certain gas in expanded from (1L, 10 atm) to (4L, 5 atm) against a constnt external pressure of 1atm . If the initial temperature of gas is 300K and heat capacity for the process is 50J^(@)C^(-1) , the enthalpy change during the process is: (use: 1L-atm = 100J)

    A certain mass of gas expanded from ( 1L, 10 atm) to (4 L, 5 atm) against a constant external pressure of 1 atm. If initial temperature of gas is 300 K and the heat capacity of process is 50 J//^(@)C . Then the enthalpy change during the process is : ( 1"L" "atm" underline ~ 100 J )

    The stop cock connecting the wo bulbs of equal volume at pressure 2 atm and 1 atm is opened at constant temperature then

    A certain mass of a gas is expended from [2 L, 20 atm, 300 K] to [5 L, 10 atm, 320 K] against a constant external pressure of 5 atm. If heat capacity of the gas is 100J//^(@)C then enthalapy change of the process will be : [1 atm lit. = 100 J]

    Home
    Profile