Calculate the work done during compression of 2 mol of an ideal gas from a volume of `1m^(3)` to `10 dm^(3)` 300 K against a pressure of 100 KPa .

Options

A. -99 kJ
B. +99 kJ
C. +22.98 kJ
D. -22.98 kJ

Answer

B

Explanation

`W=-P_("ext")Delta V, Delta V=(0.01 m^(3)-1 m^(3))=-0.99 m^(3)`
`=-100 kPa (-0.99) m^(3)`
`=99 kJ`