Home
Class 12
CHEMISTRY
The number of ions furnished by K(2)*PtC...

The number of ions furnished by `K_(2)*PtCl_(6)` in solution are

A

zero

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
D

`K_(2)PtCl_(6) to 2K^(+)+PtCl_(6)^(-)`
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|40 Videos
  • CHEMISTRIY IN EVERYDAY LIFE

    MARVEL PUBLICATION|Exercise TEST YOUR GRAPS|24 Videos
  • D AND F BLOCK ELEMENTS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|60 Videos

Similar Questions

Explore conceptually related problems

The total number of ions furnished by K_(4)[Fe(CN)_(6)] in solution is

Compound PdCl_(4).6H_(2)O is a hydrated complex, 1 m aqueous solution of it has freezing point 269.28 K . Assuming 100% ionization of complex, calculate the number of ions furnished by complex in the solution.

IUPAC name of K_(2)[PtCl_(6)] is

An aqueous solution containing 0.25 moles of a non-volatile but strong electrolyte solute ' "X" ' ' in 500g water freezes at -2.79^(@)C .The number of ions furnished in water per formula unit of ' "X" ' is (K_(f)=1.86)

Number of ions present in K_4[Fe(CN)_6]

When potash alum is dissolved in water, the total number of ions furnish in aqueous solution is