23 g of sodium will react with methyl alchol to give :

Options

A. half mole of `H_2`
B. one mole of `O_2`
C. one mole of `H_2`
D. either b or c

Answer

A

Explanation

`underset( 1 " Mole")(CH_3OH)+underset( " 1 Mole")(Na)to underset("1 Mole")(CH_3ONa)+(1/2 "Mole")(1/2H_2)`
( 1 Mole of Na is 23 g of Na )