Home
Class 12
CHEMISTRY
The organic compound (A) and (B) reacts ...

The organic compound (A) and (B) reacts with sodium metal and release `H_2` gas. Then (A) and (B) reacts each other to give methly propanoate . The compound (A) and (B) are

A

`CH_3OH and C_2H_5OH`

B

`C_2H_5OH and CH_3COOH`

C

`CH_3OH and C_2H_5COOH`

D

`CH_3OH and HCOOH`

Text Solution

Verified by Experts

The correct Answer is:
C
(a) (A) and (B) are an alcohol and an acid . Since they liberate `H_2` gas on reaction with Na.
(b) (A) and (B) react with each other to give methyl propanoate .
`:. CH_3OH+CH_3CH_2COOH underset(Delta) overset(conc. H_2SO_4)to CH_3CH_2COOCH_3+H_2O`
Promotional Banner

Topper's Solved these Questions

  • ALCOHOL,PHENOLS AND ETHERS

    MARVEL PUBLICATION|Exercise Test your Grasp : Alcohols and Phenols|40 Videos

  • ALCOHOL,PHENOLS AND ETHERS

    MARVEL PUBLICATION|Exercise Test your Grasp : Ethers|30 Videos

  • ALDEHYDES,KETONES AND CARBOXYLIC ACIDS

    MARVEL PUBLICATION|Exercise CARBOXYLIC ACIDS|198 Videos

Similar Questions

Explore conceptually related problems

Both the compounds 'A' and 'B' react with sodium metal to liberate hydrogen gas and react with each other to give Methylethanoate. The compound 'A' and 'B' are

An organic compound A reacts with sodium metal and forms B. On heating with conc. H_(2)SO_(4) , A gives diethyl ether. So A and B are

Compound A reacts with Na metal to give B. A also reacts with PCl_(5) to give C. B and C reacts with each other to give dimethyl ether. Then A, B and C respectively are