A reaction between ethyl alcohol and conc. Sulphuric acid at 373K gives

Options

A. diethyl ether
B. methyl alcohol
C. ethene
D. ethyl hydrogen sulphate

Explanation

To solve the question regarding the reaction between ethyl alcohol (C2H5OH) and concentrated sulfuric acid (H2SO4) at 373 K, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are ethyl alcohol (C2H5OH) and concentrated sulfuric acid (H2SO4).

2. **Understand the Reaction Conditions**:
- The reaction takes place at a temperature of 373 K.

3. **Reaction Mechanism**:
- When ethyl alcohol reacts with concentrated sulfuric acid, it undergoes a dehydration reaction where a water molecule is removed.
- The concentrated sulfuric acid acts as a dehydrating agent.

4. **Formation of Ethyl Hydrogen Sulfate**:
- The reaction can be represented as follows:
\[ C2H5OH + H2SO4 \rightarrow C2H5OSO3H + H2O \]
- Here, ethyl hydrogen sulfate (C2H5OSO3H) is formed along with the removal of a water molecule (H2O).

5. **Conclusion**:
- Therefore, at 373 K, the product of the reaction between ethyl alcohol and concentrated sulfuric acid is ethyl hydrogen sulfate.

### Final Answer:
The reaction between ethyl alcohol and concentrated sulfuric acid at 373 K gives **ethyl hydrogen sulfate (C2H5OSO3H)**.

---