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Diethyl ether (C2H5-O-C2H5) on boiling w...

Diethyl ether `(C_2H_5-O-C_2H_5)` on boiling with dilute `H_2SO_4` under pressure gives

A

`C_2H_5OH`

B

`C_2H_5HSO_4`

C

`CH_3CHO`

D

`C_2H_5OH and C_2H_5I`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what diethyl ether `(C2H5-O-C2H5)` yields when boiled with dilute `H2SO4` under pressure, we can follow these steps: ### Step 1: Understand the Reactants We have diethyl ether, which has the formula `C2H5-O-C2H5`. It is an ether, and we are reacting it with dilute sulfuric acid (`H2SO4`). The dilute sulfuric acid indicates that there is a significant amount of water present in the solution. **Hint:** Identify the reactants and their structures before proceeding with the reaction. ### Step 2: Analyze the Reaction Conditions The reaction occurs under boiling conditions and under pressure. This means that the ether will be subjected to higher temperatures and pressures, which can facilitate the breaking of chemical bonds. **Hint:** Consider how heat and pressure can influence chemical reactions, particularly bond breaking. ### Step 3: Identify Bond Breaking In the presence of dilute sulfuric acid, the ether undergoes hydrolysis. The ether bond (C-O) will break, and water will be added to the structure. The sulfuric acid will provide protons (H+) that will assist in this process. **Hint:** Focus on the mechanism of hydrolysis and how water interacts with the ether. ### Step 4: Formation of Alcohol As the ether bond breaks, we can expect the formation of ethyl alcohol (ethanol, `C2H5OH`). Each `C2H5` group from the ether will combine with a hydroxyl group (OH) from water, resulting in two moles of ethanol. **Hint:** Keep track of the products formed from the reactants and how they combine during the reaction. ### Step 5: Write the Final Equation The overall reaction can be summarized as: \[ C2H5-O-C2H5 + H2O \xrightarrow{H2SO4} 2 C2H5OH \] This indicates that diethyl ether reacts with water in the presence of sulfuric acid to produce two moles of ethanol. **Hint:** Write down the balanced chemical equation to visualize the reactants and products clearly. ### Conclusion When diethyl ether is boiled with dilute sulfuric acid under pressure, it yields two moles of ethyl alcohol (ethanol). **Final Answer:** The product is Ethanol (`C2H5OH`). ---

To solve the problem of what diethyl ether `(C2H5-O-C2H5)` yields when boiled with dilute `H2SO4` under pressure, we can follow these steps: ### Step 1: Understand the Reactants We have diethyl ether, which has the formula `C2H5-O-C2H5`. It is an ether, and we are reacting it with dilute sulfuric acid (`H2SO4`). The dilute sulfuric acid indicates that there is a significant amount of water present in the solution. **Hint:** Identify the reactants and their structures before proceeding with the reaction. ### Step 2: Analyze the Reaction Conditions ...
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