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3-Pentanone on reduction with Zn(Hg), HC...

3-Pentanone on reduction with Zn(Hg), HCl gives

A

Pentane

B

Pentanol

C

3-Pentanol

D

3-Pentanal

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3)-underset(O)underset(||)(C)-CH_(2)-CH_(2)-CH_(3)+4[H] underset(Delta)overset(Zn(Hg)+conc.HCl)(rarr)underset("n-Pentane")(CH_(3)-(CH_(2))_(3)-CH_(3))+H_(2)O`
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