Acetone is prepared by oxidation of

Options

A. Acetic acid
B. Methyl alcohol
C. Propan-1-ol
D. Propan-2-ol

Answer

To determine which compound can be oxidized to form acetone, we need to analyze each option provided in the question. Acetone, also known as propanone, has the chemical structure CH3COCH3.

### Step-by-Step Solution:

1. **Identify Acetone**:
- Acetone is chemically represented as CH3COCH3, which is also known as propanone.

2. **Examine Option A (Acetic Acid)**:
- Acetic acid has the formula CH3COOH.
- Upon oxidation, acetic acid will yield carbon dioxide (CO2) and water (H2O), not acetone.
- **Conclusion**: Option A is incorrect.

3. **Examine Option B (Methyl Alcohol)**:
- Methyl alcohol, or methanol, is represented as CH3OH.
- The oxidation of methanol leads to the formation of formic acid (HCOOH).
- **Conclusion**: Option B is incorrect.

4. **Examine Option C (Propane-1-ol)**:
- Propane-1-ol has the formula CH3CH2CH2OH.
- Oxidation of propane-1-ol results in propanoic acid (CH3CH2COOH).
- **Conclusion**: Option C is incorrect.

5. **Examine Option D (Propane-2-ol)**:
- Propane-2-ol is represented as CH3CHOHCH3.
- Upon oxidation, propane-2-ol produces acetone (CH3COCH3).
- **Conclusion**: Option D is correct.

### Final Answer:
- **Acetone is prepared by the oxidation of Propane-2-ol (Option D).**

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