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If we reduce 3x+3y+7=0 to the form xcosa...

If we reduce `3x+3y+7=0` to the form `xcosalpha+ysinalpha=p ,` then the value of `p` is `7/(2sqrt(3))` (b) `7/3` (c) `(3sqrt(7))/2` (d) `7/(3sqrt(2))`

A

`(7)/(2sqrt(3)) `

B

`(7)/(3)`

C

`(3sqrt(7))/(2)`

D

`(7)/(3sqrt(2)) `

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The correct Answer is:
D
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