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If: f(theta)=log((1+theta)/(1-theta)), t...

If: `f(theta)=log((1+theta)/(1-theta)),` then: `f((2theta)/(1+theta^2))=`

A

`[f(theta)\]^2`

B

`[f(theta)]^3`

C

`2.f(theta)`

D

`3.f(theta)`

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The correct Answer is:
C
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