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The pdf of a curve X is f(x)={{:(k/sqr...

The pdf of a curve X is
`f(x)={{:(k/sqrtx","0ltxlt4),(0","xle0" or "xge4):}`
Then , `P(Xge1)` is equal to

A

0.2

B

0.3

C

0.4

D

0.5

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The correct Answer is:
D
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