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If ABCDEF is a regular hexagon , then ...

If ABCDEF is a regular hexagon , then
`bar(AB) + bar(AC) + bar(AE) + bar(AF)` =

A

`4bar(AD)`

B

`3bar(AD)`

C

`2bar(AD)`

D

`bar(AD)`

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Knowledge Check

  • If ABCDEF is a regular hexagon, then bar(AC) + bar(AD) + bar(EA) + bar(FA) =

    A
    `2bar(AB)`
    B
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    C
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    D
    `bar0`

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    A
    `4bara`
    B
    `1/4bara`
    C
    `2bara`
    D
    `1/2bara`

  • If ABCDE is a regular penatagon then : bar(AB)+bar(BC)+bar(AD)+bar(ED)+bar(AE)=

    A
    `bar(AC)-2bar(DC)`
    B
    `3bar(AC)-2bar(DC)`
    C
    `bar(CA)-bar(DC)`
    D
    `3bar(AC)-bar(DC)`

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