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The function f(x) = (x^(3)+x^(2)-16x+20)...

The function `f(x) = (x^(3)+x^(2)-16x+20)/(x-2)` is not defined at x = 2. In order to make f(x) continuous at x = 2 , the value of f(2) should be defined as

A

0

B

1

C

2

D

3

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The correct Answer is:
a
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