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If f(t) = 1/(t^(2)-t-6) and t = 1/(x-2) ...

If f(t) = `1/(t^(2)-t-6) and t = 1/(x-2)` then the values of x which make the function f discontinuous are

A

`2, 2/3,7/3`

B

`2,3/2,7/3`

C

`2,3/2,3/7`

D

`1,2,1/2`

Text Solution

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The correct Answer is:
a,b,c,d
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