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If f(x) {:(=ax^(2)+b", if " 0 le x lt ...

If f(x) `{:(=ax^(2)+b", if " 0 le x lt 1 ),(=x+3 ", if " 1 lt x le 2 ),(=4 ", if " x = 1 ):}`
then the values of (a,b) for which f(x) cannot be continuous at x = 1 are

A

`(1,3)`

B

`(2,2)`

C

`(4,1)`

D

`(4,0)`

Text Solution

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The correct Answer is:
a,b,c,d
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