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A ray of light suffers minimum deviation...

A ray of light suffers minimum deviation when incident on an equilateral prism of refractive index `sqrt2` . What is the angle of incidence ?

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
When the ray suffers minimum deviation in a prism , `n = (sin (( A + delta_(m))/(2)))/(sin ((A)/(2)))`
where `i= (A + delta_(m))/(2) and r = (A)/(2)`
`therefore n = (sin i)/(sin r)`
`therefore sin i= n sin r =sqrt2 xx sin 30^(@) = (sqrt2)/(2) = (1)/(sqrt2)`
`therefore i= 45^(@)`
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